Q. 524.1( 18 Votes )
A compound C (molecular formula, C2H4O2) reacts with Na metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet smelling compound S (molecular formula, C3H6O2). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved.
C is ethanoic acid or acetic acid (CH3COOH).
R is sodium acetate or sodium ethanoate (CH3COONa) and the gas evolved is hydrogen.
A can be methanol (CH3OH) or ethanol (C2H5OH).
S is ester or methyl acetate (CH3COOCH3), an ester.
The reactions involved in this process are as follows:
1. 2CH3COOH + 2Na → 2CH3COONa + H2
2. CH3COOH + CH3OH + Conc. H2SO4→ CH3COOCH3 + H2O
3. CH3COOH + NaOH → CH3COONa + H2O
4. CH3COOH + NaOH → CH3COONa+ CH3OH
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