Answer :

Given:

Inductance of the coil: L = 0.01 H

Resistance of the coil : R = 1 Ω

Supply voltage: V = 200 V

Frequency: f = 50 Hz

Formula used:

Impedance of the circuit is given as

Here, Z is the impedance, R is the resistance and X_{L} is the inductive reactance.

X_{L} = 2πfL

∴ X_{L} = 2× π × 50× 0.01

∴ X_{L} = 3.14 Ω

Substituting we get,

∴ Z = 3.29 Ω

Now, expression for phase of the circuit is:

∴ ϕ = 72.33°= 1.26 radians

Time lag is given as:

∴ t = 4×10^{-3} seconds

Hence, impedance of the circuit is 3.29 Ω and time lag between max. alternating voltage and current is 4 ms.

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