Q. 45

# A circular loop of radius 4.0 cm is placed in a horizontal plane and carries an electric current of 5.0 A in the clockwise direction as seen from above. Find the magnetic field.(a) at a point 3.0 cm above the center of the loop(b) at a point 3.0 cm below the center of the loop.

Given:

Radius of circular loop(r) = 4 cm = 0.04 m

Current carried by it(i) = 5 A Formula used:

Magnetic field at a distance x from the center of a current carrying circular loop(B), Where

μ0 = magnetic permeability of vacuum = 4π x 10-7 T m A-1,

i = current carried by coil,

(a) To find the magnetic field 3 cm above the loop:

Magnetic field, Here, x = 3 cm = 0.03 m

Hence, substituting the given values: = 4.019 x 10-5 T (in the downward direction, by right hand thumb rule) (Ans)

(b) To find the magnetic field 3 cm below the loop:

Here, all the values are same as the previous part. Hence,

B = 4.019 x 10-5 T (in the upward direction, by right hand thumb rule)

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