Answer :

Potential energy of a loop in a uniform magnetic field is given by

U=-MBcosθ where,

M is magnetic moment of the current carrying loop,

B is magnetic field in which the loop is kept,

θ is the angle between M and B.

So, the change in potential energy of the loop will give the work done by the magnetic field as initial and final kinetic energy is 0. Since, there is no change in angle between M bad B when we are rotating the loop along the axis perpendicular to its plane so, there will be no change in the potential energy of the loop. And, W= U_{f} – U_{i}, where U_{i} is initial potential energy of the loop and U_{f} is final energy of the loop. So, W=0.

Hence, our answer is option (d).

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