# A charged particl

Starting with option (a), if E = 0, B ≠ 0 then a particle can move with same velocity only if the angle between its velocity and the magnetic field in which it is travelling is having 0o angle between them as force on a moving charged particle is given by F=qv×B where q is charge of the particle, v is velocity of the charged and B is magnitude of the magnetic field.

(b) if E ≠ 0, B ≠ 0. In this case a particle can have same velocity if velocity of the particle, electric field and magnetic field are perpendicular to each other such that the force due to magnetic field and force due to electric field cancel each other. In other words, the Lorentz force equals to zero then only the particle can move with same velocity.

(c) if E ≠ 0, B = 0. In this case the particle can’t move with same velocity as it will experience force due to electric field due to which either it will change its direction or speed or both.

(d) E = 0, B = 0. In this case because the charged particle will not experience any force so it will move with same velocity.

Hence, correct answers are (a), (b) and (d).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

A deuteron and anPhysics - Board Papers

An electron and aPhysics - Exemplar

An electron enterPhysics - Exemplar

Two charged partiPhysics - Exemplar

The magnetic forcPhysics - Exemplar

Show that a forcePhysics - Exemplar

Consider a wire cPhysics - Exemplar