Q. 345.0( 1 Vote )

A charged particle is accelerated through a potential difference of 12 kV and acquires a speed of 1.0 × 108ms–1. It is then injected perpendicularly into a magnetic filed of strength 0.2 T. Find the radius of the circle described by it.

Answer :


Given-


Applied potential difference to the charged particle , V = 12 kV = 12 × 103 V


Speed acquire by the charged particle, v =1.0 × 106 m s−1


Perpendicular Magnetic field B = 0.2 T


We know


The kinetic energy acquired by the particle is produced due to


applied potential difference, hence






and



where,


m is the mass of a proton


v= velocity of the particle


B = magnetic force


q= charge on the particle





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