Q. 85.0( 3 Votes )

A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law, find the flux of the electric field due to this charge through the surface of the hemisphere (figure).



Answer :


Given:


Charge Q placed at centre of imaginary hemispherical surface


Concept: Consider the hemisphere to be one half of an imaginary sphere in which charge Q is at the centre



We know that,


By Gauss’s law, flux of net electric field (E ) through a closed surface S equals the net charge enclosed (qin) by the surface divided by ϵ0



Net charge enclosed by the sphere Qin=Q


Therefore from Gauss’s law flux of electric field through this sphere



Since charge is symmetrically located with respect to sphere equal flux pass through each part of sphere of equal area. Therefore flux passing through both the hemispherical surfaces at the top and bottom are the same


So the flux passing through the hemispherical surface =


Therefore flux passing of electric field due to this charge through the surface of the hemisphere is Q/2ϵ0


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Kirchoff's Law for VoltageFREE Class
Few Applications of Gauss's law54 mins
All About Faraday's law55 mins
Kirchoff's Voltage Law41 mins
Kirchoff's current & Voltage lawFREE Class
Questions based on Kirchoff's Law for Voltage67 mins
Learn Raoult's Law56 mins
Ohm's Law - Full Concept in one Go59 mins
NCERT Important Questions of Gauss's Law43 mins
Interactive Quiz on Kirchoff's Law38 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :