Q. 64.5( 6 Votes )

A charge Q is placed at a distance a/2 above the centre of a horizontal, square of edge a as shown in figure. Find the flux of the electric field through the square surface.



Answer :


Given:


Length of square edge=a


Distance of charge Q above the center=a/2


Concept: Imagine the square to be one face of a cube of side a with the center at a point where charge Q is placed.


Since charge is placed at centre it is placed symmetrically with respect to all the faces of the cube . therefore we can say that equal flux passes through all the six surfaces.


flux passing through each surface


We know that,


By Gauss’s law, flux of net electric field through a closed surface equals the net charge enclosed by the surface divided by ϵ0




(as qin=Q)


Therefore flux of electric field through square surface is given by Q/6ϵ0


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