# A charge Q is placed at a distance a/2 above the centre of a horizontal, square of edge a as shown in figure. Find the flux of the electric field through the square surface.

Given:

Length of square edge=a

Distance of charge Q above the center=a/2

Concept: Imagine the square to be one face of a cube of side a with the center at a point where charge Q is placed.

Since charge is placed at centre it is placed symmetrically with respect to all the faces of the cube . therefore we can say that equal flux passes through all the six surfaces.

flux passing through each surface

We know that,

By Gauss’s law, flux of net electric field through a closed surface equals the net charge enclosed by the surface divided by ϵ0

(as qin=Q)

Therefore flux of electric field through square surface is given by Q/6ϵ0

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