Answer :

Explanation:


Given,


Charge on plate 1, Q1 = 20 μC


Charge on plate 2, Q2 = 0C Since no charge is given to the other plate and the setup is isolated)


Capacitance of the capacitor, C= 10 μF


Formula used


We know that for a capacitor with net charge, Q and capacitance, C, the Potential difference deceloped in between the plates, V is,



The charges on the inner plates of the capacitor with plates having charges Q1 and Q2 is,



Note: Charges on the outer plates of the capacitor with plates having charges Q1 and Q2 is,



In the given question, the charges on the inner plates , according to above formulas,



Hence from eqn.1, the potential difference



Hence the potential difference developed in between the plates is 1V.


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