Answer :

Electrical Intensity ( for a point charge at a distance from the ring

A ring is placed in this experiment for the finding of electrical intensity is of radius r, and a uniformly positive charge is distributed on the ring.

The charge density () on the above ring is

Due to perpendicular charge density on them the electrical components cancels each other out.

Therefore, the magnitude of electrical field is

where

is the Electrical Intensity, is the charge, is the distance between ring centre and the charge, a is the radius of the ring.

Now

a). If the distance x = 0, then the intensity is

Electrical Intensity = 0

b). If the distance x>>a, then the intensity is

Electrical Intensity =

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