Q. 154.4( 23 Votes )

A car starts from rest and moves along the x-axis with constant acceleration 5 m s–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

Answer :

As the car moves from rest, where u = 0,

Acceleration, a = 5ms-2


time, t = 8sec


distance(s) =?


From the equation of motion


S1 = ut + 1/2 at2


S1 = (0x8) + 1/2 x 5 x (8)2


S1 = 0 +1/2x5x64


S1 = 5x32


S1 =160 m


The velocity after 8 sec,


From equation of motion


v = u + at


v = 0 + 5 x 8


v = 40m/s


So, the distance travelled in 4 sec (12 s – 8 s = 4s)


S2 = 40 x 4


S2 = 160 m


Therefore, total distance travelled by the car = S1 + S2


= 160 + 160


= 320 m


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