Q. 34.8( 4 Votes )
A car moves at a constant speed on a road as shown in figure below the normal force by the road on the car is NA and N9 when it is at the points A and B respectively.
A. NA = NB
B. NA > NB
C. NA < NB
D. insufficient information to decide the relation of NA and NB.
Both A and B are on the crest of curves where car weight mg is acting perpendicular to the surface. But due to the car
motion on the curve there will be reduction in its weight equal to , m being mass of car, v velocity of car and r is radius of curve. This reduction is inversely proportional to r. so, smaller the r greater is the value of . Now from the diagram we see A r at point A is smaller than point B. Hence, normal forces at these points will be equal to the apparent weight at these points.
So, NA < NB.
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