Q. 153.7( 11 Votes )

# A car accelerates from 6 ms^{–1} to 16 ms^{–1} in 10 sec. Calculate (a) the acceleration and (b) the distance covered by the car in that time.

Answer :

Initial velocity = u

u = 6m/s

Final velocity = v

V = 16m/s

Time = t = 10 s

• Acceleration = a

a = (v-u) / t

= (16-6)/10

= 1 m/s^{2}

• Distance = s

s =

s =

= 110 m

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