Answer :


Initially, the charge on the capacitor = 50 μC

Now, let the dielectric constant of the material inserted in the gap be k.

When this dielectric material is inserted, 100 μC of extra charge flows through the battery

Therefore , the net charge on the capacitor becomes

50 + 100 = 150 μC

Now, we know capacitance of a material is given by –

Where q is charge on the capacitance and v is the applied voltage


Where A is the plate area and 0 is the permittivity of the free space.

Initially, without dielectric material inserted, capacitance is given by


Similarly, with the dielectric material place, capacitance is given by


On dividing 1) by 2), we get

Thus, the dielectric constant of the given material is 3.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A capacitor is maPhysics - Exemplar

A parallel plate Physics - Exemplar

The battery remaiPhysics - Exemplar

A parallel-plate HC Verma - Concepts of Physics Part 2

How many time conHC Verma - Concepts of Physics Part 2

The plates of a cHC Verma - Concepts of Physics Part 2

A capacitor of caHC Verma - Concepts of Physics Part 2