Q. 14.3( 13 Votes )

A capacitor of ca A.

B.

C.

D. zero

Answer :

Given: a capacitor of capacitance C charged to a potential V

Gauss’s law:


Electric flux ϕ) through a closed surface S is given by



Where,


Q is the charge enclosed by S


εo is the permittivity of the free space


According to the gauss law


Electric flux,


Where


Q is the total charge enclosed in the gaussian surface


εo is the absolute permittivity of the vacuum


Since, the two plates of capacitor contains equal and opposite charges


Total charge enclosed by the surface Q-Q=0


Putting the values of total charge in gauss law, we get





the electric flux through the closed surface enclosing the capacitor=0.

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