Q. 14.3( 13 Votes )

A capacitor of ca A.



D. zero

Answer :

Given: a capacitor of capacitance C charged to a potential V

Gauss’s law:

Electric flux ϕ) through a closed surface S is given by


Q is the charge enclosed by S

εo is the permittivity of the free space

According to the gauss law

Electric flux,


Q is the total charge enclosed in the gaussian surface

εo is the absolute permittivity of the vacuum

Since, the two plates of capacitor contains equal and opposite charges

Total charge enclosed by the surface Q-Q=0

Putting the values of total charge in gauss law, we get

the electric flux through the closed surface enclosing the capacitor=0.

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