A bullet of mass 20kg is fired horizontally with a velocity of 150m/s from a pistol of mass 2kg. Find recoil velocity.

Mass of bullet = 20kg

Mass of pistol = 2kg

Velocity of pistol= 150m/s

Let, m1 = 20kg

m2 = 2kg

u1 = 0m/s

u2 = 0m/s

v1 = 150m/s

v2 =?

According to Law of Conservation of Momentum,

Initial Momentum = Final Momentum

m1u1 + m2u2 = m1v1 + m2v2

(20kg × 0m/s) + (2kg × 0m/s) = (20kg × 150m/s) + (2kg × v2)

0 = 3000 + 2v2

–1500m/s = v2

NOTE: Negative sign denotes that pistol moves opposite to that of the bullet.

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