Q. 264.6( 23 Votes )

# A bullet of

Answer :

Firstly, we have to calculate the acceleration of the bullet:

Initial velocity, u = 150 m/s (Given)

Final velocity, v = 0 (As the bullet comes to rest after striking the wooden block)

Time, t = 0.03 s(Given)

We know that,

v = u + at

Putting the Values in the equation,We get:-

0 = 150 + a × 0.03

0.03 a = - 150

a = - a = (- 5000 ms2)

Now, we will calculate the distance of penetration of bullet:

We know that,

v2 = u2 + 2as

(0)2 = (150)2 + 2 × (-5000) × s

0 = 22500 – 10000 × s

10000 s = 22500

s = s = 2.25 m

Now, we have to calculate the magnitude of the force:

We know that:-
Force, F = m × a

F = kg × (-5000) m/s (1 gram=1/1000 kg)

= -50 N

Thus the magnitude of retarding force is exerted by the wooden block on the bullet is 50 N

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