Q. 9

# A bullet of mass 10 g is fired horizontally with a velocity of 150 ms–1 from a pistol of mass 2 kg. Find the recoil of the pistol.

Given:

Mas of bullet = 10g

Velocity of bullet = 150ms-1

Mass of pistol = 2 kg

Due to the law of conservation of momentum the momentum of the bullet is equal to the recoil of the gun. So the sum of the momentum of both the objects is equal to zero.

MbVb = –MgVg , Now ,

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
What is Impulse?44 mins
Lakhmir Singh | Force and Laws of Motion Part-347 mins
Newton's First Law of Motion48 mins
Newton's first law and Inertia34 mins
Lets solve the Numericals46 mins
Lakhmir Singh | Force and Laws of motion Part-232 mins
Quiz | Conservation of Momentum33 mins
Foundation | How to Calculate Tension Force (Part-1)43 mins
Lets understand Circular Motion42 mins
Lakhmir Singh | Force and Laws of Motion Part 142 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses