Q. 21

# A brass plate hav

Answer :

Given-
Current passing, i = 15 A
Surface area of the plate = 200 cm2,
Thickness of silver deposited= 0.1 mm = 0.01 cm

Volume of Ag deposited on one side = 200 × 0.01 cm3 = 2 cm3

Volume of Ag deposited on both side = 2 ×2 cm3 = 4 cm3

The specific gravity of silver = 10.5

Atomic weight = 107.9 g mol–1

Now, mass of silver deposited, m can be calculated

m = Volume × Specific gravity × 1000

putting the value in the above formula, we get

= 4 × 10-3 × 10.5 ×1000

= 42 kg

Using the formula, from faraday’s law of electrolysis – where,

m = the mass of the substance deposited on the electrode

z=electrochemical equivalence

i=current passing

t=time taken

Substituting the values    Rate this question :

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