# A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?

Let M = 3 kg(the mass of the bomb)

m1 = 2 kg(mass of one of the pieces)

m2 = 1 kg(mass of the other piece)

v   =0  m/s
v1 = 3 m/s

v2 = ?

Initial momentum = 0(because the bomb was at rest)

According to, the law of conservation of  linear momentum,

Initial momentum = final momentum

M × v = m1 × v1 + m2 × v2
3  ×  0  =  2  ×  3    +  1   × v2 Rate this question :

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