Q. 64.7( 6 Votes )

# A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?

Answer :

Let M = 3 kg(the mass of the bomb)

m_{1} = 2 kg(mass of one of the pieces)

m_{2} = 1 kg(mass of the other piece)

v =0 m/s

v_{1} = 3 m/s

v_{2} = ?

Initial momentum = 0(because the bomb was at rest)

According to, **the law of conservation of linear momentum**,

Initial momentum = final momentum

M × v = m_{1 × }v_{1} + m_{2 × }v_{2}3 × 0 = 2 × 3 + 1 × v_{2}

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