Q. 64.7( 6 Votes )
A bomb of mass 3 kg, initially at rest, explodes into two parts of 2 kg and 1 kg. The 2 kg mass travels with a velocity of 3 m/s. At what velocity will the 1 kg mass travel?
Let M = 3 kg(the mass of the bomb)
m1 = 2 kg(mass of one of the pieces)
m2 = 1 kg(mass of the other piece)
v =0 m/s
v1 = 3 m/s
v2 = ?
Initial momentum = 0(because the bomb was at rest)
According to, the law of conservation of linear momentum,
Initial momentum = final momentum
M × v = m1 × v1 + m2 × v2
3 × 0 = 2 × 3 + 1 × v2
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