# A body of m

Mass of body = 5kg = m

Initial speed = 10m/s = u

Kinetic energy =

= × 5kg × (10m/s)2

= × 5 × 100

= 250J

Final speed = 0m/s (at highest point)

Using 3rd equation of motion.

v2 = u2 – 2gs

(0)2 = (10m/s)2 – 2(9.8m/s2) s

0 = 100 – 19.6s

–100 = –19.6s

= s

5.102m = s = h

Potential energy = mgh

= 5 × 9.8 × 5.102

= 249.98J = 250J (approx.)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Kinetic and Potential Energy39 mins
Work and Types of Work done40 mins
Conservation of Energy41 mins
Chapter Test45 mins
Elections- Mechanism and Types48 mins
Constitution - Formation and Objective63 mins
Construction-244 mins
Construction-145 mins
PYQ's Practice -Construction47 mins
Probability-246 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Name the devices Lakhmir Singh & Manjit Kaur - Physics

Which one of the Lakhmir Singh & Manjit Kaur - Physics

Name the quantityLakhmir Singh & Manjit Kaur - Physics

Define the term &Lakhmir Singh & Manjit Kaur - Physics

What are the variLakhmir Singh & Manjit Kaur - Physics