Q. 204.3( 26 Votes )

A body of mass 0.5 kg travels in a straight line with velocity v =a x3/2 where a = 5 m–1/2 s–1. What is the work done by the net force during its displacement from x = 0 to x = 2 m?

Answer :

Given,

Mass of the body, m = 0.5 kg


Velocity of the body is given by


v =a x3/2 where a = 5 m–1/2 s–1


At x = 0, initial velocity, u = 0


At x = 2, final velocity, v = 5 (2)3/2 = m s-1


According to work-energy theorem, work done is equal to the change in kinetic energy of the body.


Work done, W = ΔK


W = (1/2)mv2 – (1/2)mu2


W = (1/2) × 0.5 kg × ( m s-1)2 – (1/2) × 0.5 kg × 02


W = 50 J


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