# A body of mass 0.40 kg moving initially with a constant speed of 10 m s-1 to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = –5 s, 25 s, 100 s.

Given,

Mass of the body, m = 0.40 kg

Initial speed of the body, u = 10 m/s

Force acting on the body, F = -8 N

The force is negative because it acts in the opposite direction i.e. south to the motion of the body i.e. north.

Time for which the force acts on the body, t =30 s

According to the second law of motion, the acceleration of the body is: The third equation of motion is given as, …..(i)

Where,

‘s’ is the position of the body,

‘u’ is the initial speed of the body,

‘a’ is the acceleration of the body and

‘t’ is the time.

Given,

1. At t=-5 s

The acceleration of the body is zero since the force was applied starting t=0

u= 10 m/s

using equation (i) we get,

s=10 m/s × (-5 sec)

s= -50 m

2. At t= 25s

Acceleration, a’ = -20 m/s2 and

u = 10 m/s

using equation (i) we get, s = 250 m- 6250 m = -6000 m

3. At t=100 s

We divide this time period in two parts with displacements s’ and s”,

The first part is time 0<t≤30s,

Given,

Acceleration of the body, a = -20 m/s2

u = 10 m/s

The displacement travelled by the body using equation (i) during this time t’ is, s’= 300 m – 9000 m = -8700 m

The displacement travelled by the body till t=30 s , s’=-8700 m

The second part is 30s<t≤100s,

Given,

Acceleration of the body=0

The final velocity for the first part is the initial velocity for the second part,

From the first equation of motion, The final velocity after t=30 s is,

v= u + at

v=10 m/s+ (-20) m/s2× 30 s = -590 m/s

Thus, velocity of the body after 30 sec= -590 m/s

For, motion between 30 s to 100 s, i.e. t = 70 s, we use equation (i):

s”=v t + 0

s”= -590 m/s × 70 s = -41300 m

Thus, s = s’+ s”= -8700 m – 41300 m

s = -50000 m

The position of the body at t=-5 s, 25 s, 100 s is -50 m, -6000 m, -50000 m respectively.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Pseudo Force52 mins  Challenging Quiz on Newton Laws of Motion Part 364 mins  Elaborative Lecture on Constraint Motion59 mins  Pully Problems | Getting JEE Ready68 mins  Check your understanding of linear momentum22 mins  Why edges are raised for Curved roads? - Banking of roads54 mins  Into the world of springs - Spring force48 mins  Basics strengthener - Newton Laws of motion61 mins  Understand Newton's 2nd law Exhaustively34 mins  Escaping the reality - Concept of Pseudo Force54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 