A body of 2 kg fa

Given,

Mass of the body, m = 2kg

Initial velocity (u) = 0 m/s

Time (t) = 2s

Acceleration due to gravity (g) = 10m/s²

We need to find, Final velocity (v) =?

We know,

v = u + at

v = 0 + 10 x 2

v = 20 m/s

K.E = 1/2 (mv²)

K.E = 1/2 x 2 x (20)²

K.E = 400J

Hence, the Kinetic energy of the body during the fall at the end 2s = 400 J