Answer :


(a) Weight of the combined system = (m+M)g = N Frictional force = Given that acceleration a = Now by equating the forces along the surface we have the





(b) Let f be the frictional force acting on the smaller block, along the movement only this force is on the block whose acceleration is a =


Hence this force should be equal to mass× acceleration =


(c) Now during the displacement d, velocity of the block can be evaluated by using uniform motion equation


Now substituting for the values, we get v= , u=0


Now initial K.E =0 since u=0 and


final K.E =


Therefore, the change in K.E is =


So, work done by the frictional force on the smaller block by the larger block = change in kinetic energy ( from work energy theorem) =


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