Answer :

(a) Weight of the combined system = (m+M)g = N Frictional force = Given that acceleration a = Now by equating the forces along the surface we have the

(b) Let f be the frictional force acting on the smaller block, along the movement only this force is on the block whose acceleration is a =

Hence this force should be equal to mass× acceleration =

(c) Now during the displacement d, velocity of the block can be evaluated by using uniform motion equation

Now substituting for the values, we get v= , u=0

Now initial K.E =0 since u=0 and

final K.E =

Therefore, the change in K.E is =

So, work done by the frictional force on the smaller block by the larger block = change in kinetic energy ( from work energy theorem) =

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A balloon filled Physics - Exemplar

A rocket acceleraPhysics - Exemplar

A curved surface Physics - Exemplar

A block of mass 1Physics - Exemplar

Which of the diagPhysics - Exemplar

The kinetic energHC Verma - Concepts of Physics Part 1

Which of the diagPhysics - Exemplar

<span lang="EN-USHC Verma - Concepts of Physics Part 1

The bob of a pendHC Verma - Concepts of Physics Part 1

The magnetic forcHC Verma - Concepts of Physics Part 1