Answer :

Mass of the first block is m = 2kg


Initial speed before collision is u= 2 m/s


Mass of the second block is m’ = 2 kg


Final speed after collision is v


From law of conservation of momentum







{a} Loss in kinetic energy in elastic collision will be





{b} Actual loss = (maximum loss)/2 =2/2 =1J


Let final velocities of the blocks of masses 2kg are v1 and v2.


Where v1+v2=u and v1 - v2= eu.


Then, actual loss will be





Since, v1+v2=u and v1 - v2= eu







So, the coefficient of restitution (e) is


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