Answer :

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The mass of the block, m = 2 kg


Force that is being applied, F = 20 N


Acceleration due to gravity, g = 10 m/s2


Time for which the force acts, t = 1 s


The applied force, F = mgsinθ + ma


20 = 2×10sin37° + 2×a


20 = 12 + 2a


a = 4 m/s2


The distance travelled by the block, s = 1/2 at2


= 0.5×4×1×1 = 2m


(a.) Maximum work done = Fs


= 20 × 2


= 40 J


(b.) If the work done by the applied force = 40 J


Distance travelled by the block = work done/ force applied


= 40/20 = 2m


Height corresponding to this distance, h = 2sin37° = 1.2 m


Work done by force of gravity = -mgh


= -2 × 10 × 1.2


= -24 J


(where the negative sign indicates the that displacement is against gravity)


(c.) Speed of the block after 1s = at = 4×1 = 4 m/s


Kinetic energy corresponding to this = 1/2 mv2


= 0.5 × 2 × 4 × 4


= 16 J


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