Answer :

Mass of the block, m = 100 g = 0.1 kg

Net displacement in height of the block, h = diameter of the block = 2×10 = 20 cm = 0.2 m


Work done by gravity on the block, W = -mgh


= 0.1 × 9.8 × 0.2


= 0.196 J


Initial kinetic energy of the block = 1/2 × mass of the block × (initial speed of the block)2


= 0.5 × 0.1 × 5 × 5


= 1.25 J


Final kinetic energy of the block = 0 J (Eventually, it stops)


Change in kinetic energy of the block = 0 - 1.25 = -1.25 J


This change in kinetic energy = work done by gravity + work done by the tube


Work done by the tube = change in kinetic energy - work done by gravity


= -1.25 – 0.196


= -1.45 J


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