Q. 544.4( 12 Votes )

A block of 8 kg is moving with speed of 4 m/s on a frictionless surface. The block into the rest position by compressing the spring. The spring constant is 2 x 102 N/m. How much will the spring compressed?

Answer :

Mass of the block (m) = 8 Kg


Velocity of the block (v) = 4m/s


Spring constant (k) = 2 × 102 N/m


The kinetic energy of the block will be converted into the potential energy of the spring.






x = √0.64


x = 0.8 m


Hence, the compression of the spring is 0.8 m.


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