Answer :
Distance of nth fringe from central maxima, Xn = nλD/d
Where, λ is wavelength of light
D is distance from slits to screen
d is slit width
(a) We need to find distance of 3rd from central maxima for wavelength 650 nm
n = 3
x3 = 3 × (650 nm) D/d
(b) The distance of nth bright fringe from central maxima for two wavelengths, say λ1 and λ2, are
Xn = nλ1D/d
Yn = nλ2D/d
When bright fringe due to two wavelength coincide, their distance from central maxima is same
i.e., Xn = Yn
n1λ1D/d = n2λ2D/d
n1λ1 = n2λ2
n1/n2 = λ2 /λ1
= 520 / 650 = 8/10
Therefore, the bright fringe due to two wavelength coincide when n1 is integer multiple of 8 and n2 is integer multiple of 10.
Thus least distance for which they coincide,
S = n1 λ1D/d
= 8 × (650 nm) D/d
[The question is not complete. This question cannot be answered completely without the values of d and D.]
Rate this question :


A. Distinguish be
Physics - Board Papers(a) If one of two
Physics - Board Papers<span lang="EN-US
Physics - Exemplar<span lang="EN-US
Physics - ExemplarConsider the diff
Physics - Exemplar