The diagram is given as:
Given: Electromotive force (E) of battery = 10 volt.
Internal Resistance r of the battery = 3 Ω
Current in the Circuit (I) = 0.5 A
Let the resistance of the required resistor is R Ω
Let the Terminal voltage of the register be V.
As per Ω ’s law,
⇒R + r = 20 Ω
∵ r = 3Ω
Resistance of Resistor is 17 Ω.
Also, as per Ohm’s law,
⇒V = IR
⟹ V = 0.5A × 17Ω =
⇒ V = 8.5V
∴ Terminal voltage of the register is 8.5V.
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