# A battery of emf

The diagram is given as:

Given: Electromotive force (E) of battery = 10 volt.

Internal Resistance r of the battery = 3 Ω

Current in the Circuit (I) = 0.5 A

Let the resistance of the required resistor is R Ω

Let the Terminal voltage of the register be V.

As per Ω ’s law,

R + r = 20 Ω

r = 3Ω

Resistance of Resistor is 17 Ω.

Also, as per Ohm’s law,

V = IR

V = 0.5A × 17Ω =

V = 8.5V

Terminal voltage of the register is 8.5V.

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