Given:Initial speed of the ball, u = 40 m/sAngle of projection of the ball with the horizontal, = 60°Also,a = g = 10 m/s2(a) Maximum height reached by the ball:⇒(b) Horizontal range of the ball:

Q. 333.8( 8 Votes )

A ball is thrown

Class 11th HC Verma - Concepts of Physics Part 1 3. Rest and Motion : Kinematics

Answer :

Given:
Initial speed of the ball, u = 40 m/s
Angle of projection of the ball with the horizontal, = 60°
Also,
a = g = 10 m/s²

(a) Maximum height reached by the ball:

⇒

(b) Horizontal range of the ball:

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