Answer :

Given : height(s) = 20m

Acceleration = 10 ms^{-2}

To find the final velocity of ball as it reach the ground we will use 3rd equation of motion

We have, initial velocity(u) = 0 m/s

height(s) = 20m

Acceleration(a) = 10 ms^{-2}

The third equation of motion

To find the time taken by ball the to reach the ground we will use 1st the equation of motion

We have, initial velocity(u) = 0 m/s

Final velocity(v) = 20 m/s

Acceleration(a) = 10 ms^{-2}

1st equation of motion

v = u + at

20 = 0 + 10 t

t = = __2 s__

time taken to reach the ground is 2s

Rate this question :

When a body startTamilnadu Board Science

A body moving witTamilnadu Board Science

A train travellinTamilnadu Board Science

A ball is gently Tamilnadu Board Science

A racing car has Tamilnadu Board Science

Derive equations Tamilnadu Board Science

Derive the three Tamilnadu Board Science