Answer :


Given:
Distance travelled by the ball in 0.200 seconds = 6 m
Let:
Time, t = 0.200 s
Distance, s = 6 m
a = g = 10 m/s2 (Acceleration due to gravity).


Using the equation of motion, we get:





Let h be the height from which the ball is dropped.
We have:
u = 0 and v = 29 m/s
Now,




Total height = 42.05 + 6 = 48.05 m ≈ 48 m


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