# A ball falls to the ground as show2n below:A potential energy = 80 JKinetic energy = 0B Kinetic energy = 48 JC = potential energy = 0(a) What is the kinetic energy of ball when it hits the ground?(b) What is the potential energy of ball at B?(c) Which law you have made use of in answering this question?

a) The kinetic energy of ball when it hits the ground will be equal to the potential energy of the ball when it was about to be made to fall. Hence, the kinetic energy will be 80J.

b) The potential energy of ball at position B will be,

PE= 80 - 48

= 32J

c) With the help of law of conservation of energy which states that energy can neither be created not be destroyed but can only be changed from one form to another, the above answers can be found. Since, the total energy will remain constant in all the three given stages.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Let's Calculate Workdone by a Body42 mins
Foundation | Let us Understand Law of Conservation of Energy44 mins
Foundation | Rapid Fire Quiz36 mins
Introduction to Work40 mins
Conservation of Mass-Energy41 mins
How Does Barometer Work?36 mins
Cell Organelles of Energy Metabolism49 mins
Champ Quiz | 2-Dimension( Coordinate geometry )36 mins
Matter and Its Classification34 mins
Speed and Velocity59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses