(a) Compound A and C give tollen’s test which indicates that they are aldehydes. Compound C gives iodoform test which means it contains a carbonyl carbon so, with formula C4H80 the structure of the compound would be CH3COCH2CH3 .Now upon reduction with Zn/Hg conc. HCl, the corresponding alkanes are obtained, so reduction of B gives Butane (D, so the isomer A have to be linear chain aldehyde, giving Butane on reduction. So the last isomer possible is compound C, 2-Methyl propanal. As shown below
A is CH3 CH2 CH2CHO
(b) will be least reactive as the carbonyl carbon is sterically hindered and most reactive would be compound A towards the addition of HCN.
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