Q. 63.5( 6 Votes )

A. B. and C are t

Answer :

we know that

A is Carbon – 6C12


B is Sodium – 11Na23


C is Chlorine – 17Cl35


(i) The configuration of carbon is 1s22s22p2. It has exactly 4 electrons


in its outermost shell. So, it neither loses nor gains electrons to obtain octet. Rather it shares electrons with other atoms and gets stable by obtaining octet structure. So, it forms covalent compounds but not ionic compounds.


(ii) The configuration of sodium is 1s22s22p63s1. So, to obtain octet


and become stable, it can easily lose an electron which is 3s1. Therefore, sodium forms ionic compounds.


(iii) The Chlorine (17Cl35) configuration is 1s22s22p63s23p5. So, it can


easily gain an electron to obtain octet , thereby forming ionic compounds. But it can also share electrons and form covalent compounds like in the case of HCl. So, chlorine forms both ionic and covalent compounds.


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