Answer :


The wavelength of radiation produced by tube, λ = 0.45 Å

i.e. 0.45 × 10-10 m

(a) The maximum energy of the photon is given by,



E = Energy of photon

h = Planck’s constant = 6.6 × 10-34 Js

c = 3 × 108 ms-1

λ = wavelength of photon

by putting the values in equation (1), we get,

E = 44 × 10-16 J or 27.6 × 103 eV

The maximum energy of the photon in x-ray is 44 × 10-16J.

(b) For a photon to have 27 KeV of energy, the accelerating potential must be of the order of 30 KeV.

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