Answer :

(i) Given that E = E_{0}Sin(ωt)

I = I_{0}Sin(ωt + π/4)

It can be seen from the above two equations that phase angle of current at any point is greater than that of voltage by an amount of π/4. This means current leads the voltage in the circuit. This happens in a capacitive circuit. Therefore the element in the black box is a capacitor.

(ii)

Vc = VR

Xc = R

Impedance Z =

Z = R√2

Rate this question :

What is the area NCERT - Physics Part-I

A spherical capacNCERT - Physics Part-I

A small sphere ofNCERT - Physics Part-I

A cylindrical capNCERT - Physics Part-I

A. Find equivalenPhysics - Board Papers

An electrical tecNCERT - Physics Part-I

Three capacitors NCERT - Physics Part-I

In a parallel plaNCERT - Physics Part-I

A 12pF capacitor NCERT - Physics Part-I