Q. 25

(a) Account for t

Answer :

(a)


(i)



In ammonia molecule there is a lone pair present. We know that repulsion is of the order: lp-lp>lp-bp>bp-bp where lp is lone pair and bp is bond pair. Since there is lp-bp repulsion, lp occupies more space and hence bond angle gets decreased. While in ammonium ion there is no lone pair present so the bond angle is greater.


(ii)


In H2O molecule, H is attached to a highly electronegative atom. So there is Hydrogen bond formed between H of one molecule and O of another molecule. Through this bonding water exist as a network of molecules. These bonds are strong enough and hence H2O has a higher boiling point. While in H2S molecule there is no such possibility of H-bonding since it is a less electronegative element. Therefore it has a low boiling point when compared to H2O.


(iii) As we know size of the elements decreases down the group. So electronegativity decreases down the group because of which metallic character increases down the group. As metallic character increases reducing character decreases. Also due to inert pair effect lower oxidation states are stable on moving down the group which also says that reducing character decreases. Therefore, reducing character decreases from SO2 to TeO2.


(b)


(i) H4P2O7 (Pyrophosphoric acid)



(ii) XeF2



OR


(a)


(i) XeF4



(ii) H2S2O7



(b)


(i) when Iron is treated with HCl, the reaction releases H2 gas. Therefore ferrous chloride (FeCl2) is formed instead of ferric chloride (FeCl3).


Fe + 2HCl FeCl2 + H2


(ii)


In the above molecules, hydrogen bonded to oxygen is called the acidic proton. Acidity of a compound is defined as the ease with which it release proton. For the proton to be released easily the O-H bond must be weaken. On increasing the oxidation Number of the central atom to which O-H bond is connected acidity is increased. Since in HClO4, Cl atom is connected to 3 more O atoms bond strength weakens and acidity increases. Whereas in HClO, oxidation number of Cl atom remains the same so its proton is less acidic.


(iii) On moving down the 15th group, bond dissociation enthalpy decreases which means that these bonds are quite easy to break. Consequently, reducing character also decreases. Hence, Bi being the last element shows strong reducing property.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

On heating compouChemistry - Exemplar

Explain why NCl<sChemistry - Exemplar