Answer :

Given:

Power in the secondary coil: P_{S} = 60 W

Current through the secondary coil: I_{S} = 0.54 A

Voltage in the primary coil: Line voltage = V_{P} = 220 V

Formula used:

Power is given as

P= VI

Where V is the voltage and I is the current flowing.

Thus

Here, V_{S} is the Voltage in the secondary coil, P_{S} is the power of the secondary coil and I_{S} is the current through the secondary coil

∴ V_{S} = 111.11 V

Since V_{S} < V_{P}, transformer is a step down transformer.

We know that proportions

Hence current through the primary coil is 0.272 A.

Rate this question :

1MW power is to bPhysics - Exemplar

A 60 W load is coPhysics - Exemplar

The alternating cPhysics - Exemplar

An AC source rateHC Verma - Concepts of Physics Part 2

A device ‘X’ is cPhysics - Exemplar

An inductor-coil HC Verma - Concepts of Physics Part 2

When an AC voltagPhysics - Exemplar

For an LCR circuiPhysics - Exemplar