# A 50 turn circular coil of radius 2.0 cm carrying a current of 5.0 A is rotated in a magnetic field of strength 0.20 T.(a) What is the maximum torque that acts on the coil?(b) In a particular position of the coil, the torque acting on it is half of this maximum. What is the angle between the magnetic field and the plane of the coil?

Given-
No. of turns of the coil, n = 50

Magnetic field intensity, B = 0.20 T = 2 × 10−1 T

Radius of the coil, r = 0.02 m = 2 × 10−2 m

Magnitude of current =5 A

We know that torque acting on a rectangular coil having n turns is given by Where

B= applied magnetic field

A= area of rectangular loop

I = current flowing through coil = angle between the area vector and magnetic field

Torque is maximum if

θ = 90°.   Given that ,   So, the angle between the magnetic field and the plane of coil is given by - Rate this question :

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