Q. 233.6( 9 Votes )

A 5 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 18 cm at a distance of 12 cm from it. Use lens formula to determine the position, size and nature to the image formed.

Answer :

According to the question;

Object distance = -12cm;


Image distance = v;


Focal length = 18cm;


By lens formula;







v = -36cm.


Therefore, image is formed at 36 cm in front of lens.


Now;


Height of object h1= 5cm;


Magnification = =


Putting values of v and u


Magnification =




Height of image is 15 cm.


Thus, the image is virtual, enlarged, and erect and three times the size of object.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Introduction to Light55 mins
Foundation | How to Solve Numericals on Mirror Formula58 mins
Foundation | NTSE Most Challenging Numericals37 mins
Introduction to Spherical LensFREE Class
What is Refraction?45 mins
How to Ace Physics in NTSE 2020?41 mins
Image Formation by Concave Mirror47 mins
Light and it's Reflection58 mins
Reflection of Light - Plane Mirrors51 mins
Lets Understand The Reflection of Light49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :