Q. 114.1( 57 Votes )

A 25-watt bulb em

Answer :

Given:

Power of the bulb, P = 25 W


Wavelength of light emitted, λ = 0.57μm


By Planck’s relation we have,


Energy, E = h×v


But we know v = [c] / [λ]


Where


c = Speed of Light


v= Frequency


λ = Wavelength


So, E = hc /λ


= [[6.626×10-34] × [3×108]] / [0.57×10-6]


= [1.9878×10-25] / [0.57×10-6]


= 3.487×10-19 J


Rate of Emission of Quanta, R = P / E


Where


P = Power of the bulb


E = Energy of photon


R = [25] / [3.487×10-19]


= 7.169×1019 s-1


Therefore, the rate of emission of quanta is 7.17×1019 s-1.


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