# A 25-watt bulb em

Given:

Power of the bulb, P = 25 W

Wavelength of light emitted, λ = 0.57μm

By Planck’s relation we have,

Energy, E = h×v

But we know v = [c] / [λ]

Where

c = Speed of Light

v= Frequency

λ = Wavelength

So, E = hc /λ

= [[6.626×10-34] × [3×108]] / [0.57×10-6]

= [1.9878×10-25] / [0.57×10-6]

= 3.487×10-19 J

Rate of Emission of Quanta, R = P / E

Where

P = Power of the bulb

E = Energy of photon

R = [25] / [3.487×10-19]

= 7.169×1019 s-1

Therefore, the rate of emission of quanta is 7.17×1019 s-1.

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