Answer :
i) Calculation of number of molecules in each:
a. Given: Mass of He = 20g
Gram molecular mass of He = 4g
To calculate the number of molecules, first we apply the formula:
Number of gram molecules = 5
Now, number of molecules = 5 × 6.022 × 1023
= 3.011 × 1024
Thus, number of molecules of He is 3.011 × 1024
b. Given: Volume of NH3 at STP = 44.8L
Gram molecular mass of NH3 = 17g
First we will calculate the number of moles so that we can find the number of molecules.
As we know that 1 mole of any gas occupies 22.4 litres of volume.
∴ 1 mole of NH3 = 22.4 litre
22.4 × Number of moles = 44.8 litres
Number of moles = 2
Now, number of molecules = No. of moles × 6.022 × 1023
= 2 × 6.022 × 1023
= 1.204 × 1024
Thus, number of molecules of NH3 is 1.204 × 1024
c. Given: Volume of N2 at STP = 67.2L
Gram molecular mass of N2 = 28g
First we will calculate the number of moles so that we can find the number of molecules.
As we know that 1 mole of any gas occupies 22.4 litres of volume.
∴ 1 mole of NH3 = 22.4 litre
22.4 × Number of moles = 67.2 litres
Number of moles = 3
Now, number of molecules = No. of moles × 6.022 × 1023
= 3 × 6.022 × 1023
= 1.806 × 1024
Thus, number of molecules of N2 is 1.806 × 1024
d. 1 mol of H2SO4
Given: Number of moles = 1mol
Number of molecules = No. of moles × 6.022 × 1023
= 1 × 6.022 × 1023
= 6.022 × 1023
Thus, number of molecules of H2SO4 is 6.022 × 1023
e. Given: Mass of water = 180g
Gram molecular mass of H2O = 18g
To calculate the number of molecules, first we apply the formula:
Number of gram molecules = 10
Now, number of molecules = 10 × 6.022 × 1023
= 6.022 × 1024
Thus, number of molecules of H2O is 6.022 × 1024
The arrangement of the samples in increasing order of the number of molecules in each is:
44.8 L of NH3 at STP < 67.2 L of N2 at STP < 20 g of He < 1 mol of H2SO4 < 180 g of water
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Kerala Board Chemistry Part ICalculate t
Kerala Board Chemistry Part ICalculate t
Kerala Board Chemistry Part ICalculate t
Kerala Board Chemistry Part I