Q. 73.9( 19 Votes )
A 100W sodium lam
Answer :
(a) Energy of photon E = hv = hc/λ
Where h = plank’s constant = 6.63 × 10-34 J. sec
ν = frequency of light
c = speed of light = 3 × 108 m/s
λ = wavelength of light
E = 6.63 × 10-34 × 3 x108 / 589 × 10-9
= 3.38 × 10-19 J
Energy of a photon is equal to 3.38 × 10-19 J.
(b) Rate of photon falling on the sphere = power of lamp/energy per photon
∴ Rate of photon = 100 / 3.38 × 10-19J = 3.0 × 1020 photons/sec.
Rate at which photons are falling on the sphere is equal to 3.0 × 1020 photons/sec.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
If light of
Physics - Board PapersA. How does one e
Physics - Board PapersExplain with the
Physics - Board Papers