Answer :

Initially a mass of 500g has been added to balance the weight of the coil. Hence the weight of the coil is going to be,


Mg=Wcoil


Wcoil=500 × 10-3× 9.8 N


=0.5 × 9.8 N


Now a current of4.9 Amp has been started. So the force due to the magnetic interaction is going to be,


F=i(lB) along(lxB)


=4.9 × (0.01 × 0.2) N


=9.8 × 0.001N


But there are 100 turns. So the total force will be;


Ftotal = 100 × 9.8 × 0.001N


=9.8 × 0.1 N


Let us assume the mass to be added is m.


Hence, mg=9.8 × 0.1


m=0.1kg


So, the mass to be added is 0.1kg.


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