# A 10 kg ball is dropped from a height of 10m. Find(a) the initial potential energy of the ball ,(b) the kinetic energy just before it reaches the ground(c) the speed just before it reaches the ground.

Given data

Mass of ball (m)= 10kg

Height(h) = 10m

(a) potential energy = mgh

= 10 (kg)× 10 (m/s2) × 10 (m)

=1000 (J)

(b)when the ball reaches the ground the gravitational potential energy changes to kinetic energy

So, kinetic energy gained= 1000(J)

If we neglect the air resistance

(c) We know that Kinetic Energy = and from above data we have kinetic energy as 1000 J and mass of ball (m) as 10kg ,hence on equating for velocity we will get velocity as

V = substituting Kinetic Energy = 1000 J and mass as 10 kg ,we have

Velocity = = = 14.14 m/s

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