Answer :

Mass of bullet, m = 10 g

= 0.01 kg


Speed of bullet, v = 200 m/s


Mass of target, M = 2 kg


Combine speed after hitting target = V


Before collision, momentum of the system is = mv = 2


After collision, the bullet and target move together. Their combined mass is (m+M) = 2.01 kg


So, the momentum of the system after collision is = 2.01V


Applying conservation of momentum,


Momentum of the system before collision = momentum of the system after collision


2 = 2.01 V


V = 0.99 m/s


This is the combined velocity of the target and bullet after the collision.


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