Q. 264.0( 28 Votes )
A 1 kg block situated on a rough incline is connected to a spring of spring constant 100 N m–1 as shown in Fig. 6.17. The block is released from rest with the spring in the unstretched position. The block moves 10 cm down the incline before coming to rest. Find the coefficient of friction between the block and the incline. Assume that the spring has a negligible mass and the pulley is frictionless.

Answer :
Given,
Mass of the block, m = 1 kg
Spring constant, k = 100 N m-1
Displacement of the block, s = 10 cm = 0.1 m
The forces can be shown in the figure as follows:
At equilibrium,
Surface normal reaction force, N = mgcos37°
Frictional force, f = μN where, μ is the coefficient of friction
⇒ f = mgsin37°
Net force acting on the block, F = mgsin37° - f
⇒ F = mgsin37° - μmgcos37°
⇒ F = mg(sin37° - μcos37°)
At equilibrium, work done by the block is equal to the potential energy of the spring according to law of conservation of energy.
So, mg(sin37° - μcos37°)s = (1/2)ks2
⇒ 1 kg×9.8 m s-2×(0.602 – μ0.799)×0.1 = (1/2)×100Nm-1×(0.1)2
⇒ 0.602 - μ × 0.799 = 0.51
⇒ μ × 0.799 = 0.092
⇒ μ = 0.115
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PREVIOUSTwo inclined frictionless tracks, one gradual and the other steep meet at A from where two stones are allowed to slide down from rest, one on each track (Fig. 6.16). Will the stones reach the bottom at the same time? Will they reach there with the same speed? Explain. Given θ1 = 300, θ2 = 600, and h = 10 m, what are the speeds and times taken by the two stones?NEXTA bolt of mass 0.3 kg falls from the ceiling of an elevator moving down with a uniform speed of 7 m s–1. It hits the floor of the elevator (length of the elevator = 3 m) and does not rebound. What is the heat produced by the impact? Would your answer be different if the elevator were stationary?
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